(a) We have,

Point x = −1 divides the real line into two disjoint intervals i.e., (∞,-1) and (-1,∞)

Thus, f is strictly increasing for x > −1.
(b) We have,
f(x) = 10 − 6x − 2x2

The point x=3/2 divides the real line into two disjoint intervals

(c) We have,
f(x) = −2x3 − 9x2 − 12x + 1

Points x = −1 and x = −2 divide the real line into three disjoint intervals
∴ f is strictly decreasing for x < −2 and x > −1.

The point x =9/2 divides the real line into two disjoint intervals i.e.,


The points x = −1, x = 1, and x = 3 divide the real line into four disjoint intervals
