Find the least value of a such that the function f given f(x)=x^2+ax+1 is strictly increasing on (1, 2).

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asked Jan 20, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 947

Find the least value of a such that the function f given f(x)=x2+ax+1 is strictly increasing on (1, 2).

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answered Jan 20, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 20, 2018 by sforrest072
 
Best answer

We have,

Now, function f will be increasing in (1, 2), if f'(x)>0 in (1, 2).

Therefore, we have to find the least value of a such that Thus,

Thus, the least value of a for f to be increasing on (1, 2) is given by,

Hence, the required value of a is −2.

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