
It is noted that the ammeter has been put in series with
the circuit and the voltmeter has been put in a parallel with12Ω resistor.
(i) Calculation of current reading in the ammeter:

(ii) Calculation of potential difference reading across 12
Ω resistor.
Current,I=0.24A,Resistance,R =12Ω, Potential difference,V =?
Applying Ohm's law
v = IR= 0. 24 x 12= 2.88 V
Therefore, the voltmeter reading is 2.88 V.