Find points at which the tangent to the curve y = x^3 − 3x^2 − 9x + 7

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asked Jan 22, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949
recategorized Jan 22, 2018 by sforrest072

Find points at which the tangent to the curve y = x3 − 3x2 − 9x + 7 is parallel to the x-axis.

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answered Jan 22, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 22, 2018 by sforrest072
 
Best answer

The equation of the given curve is 

Now, the tangent is parallel to the x-axis if the slope of the tangent is zero.

When x = −1, y = (−1)3 − 3 (−1)2 − 9 (−1) + 7 = −1 − 3 + 9 + 7 = 12. Hence, the points at which the tangent is parallel to the x-axis are (3, −20) and (−1, 12).

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