Find the equation of the tangent to the curve y =√(3x-2) which is parallel to the line 4x − 2y + 5 = 0.

0 votes
24 views
asked Jan 22, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949
Find the equation of the tangent to the curve y =√(3x-2) which is parallel to the line 4x − 2y + 5 = 0.

1 Answer

0 votes
answered Jan 22, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 22, 2018 by sforrest072
 
Best answer

The equation of the given curve is y=√(3x-2.)

The slope of the tangent to the given curve at any point (x, y) is given by,

The equation of the given line is 4x − 2y + 5 = 0.

∴Slope of the line = 2
Now, the tangent to the given curve is parallel to the line 4x − 2y − 5 = 0 if the slope of the tangent is equal to the slope of the line.

Hence, the equation of the required tangent is 48x-24y =23

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...