Find the approximate value of f (5.001), where f (x) = x^3 − 7x^2 + 15.

0 votes
17 views
asked Jan 22, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 943

Find the approximate value of f (5.001), where f (x) = x3 − 7x2 + 15.

1 Answer

0 votes
answered Jan 22, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 22, 2018 by sforrest072
 
Best answer

Hence, the approximate value of f (5.001) is −34.995.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...