Given 15 cot A = 8, find sin A and sec A.

+3 votes
162 views
asked Apr 30, 2017 in Mathematics by sforrest072 (157,439 points) 61 411 949

1 Answer

+2 votes
answered Apr 30, 2017 by Rohit Singh (61,782 points) 35 133 358

Solution:
CotA = 815 
Or
BP=815
Let B=8K and P=15k
So in a right angle triangle with angle A
P2 + B2 =H2
Or H=17K
Sin A = P/H = 15/17
Sec A = H/B = 17/8

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