Find both the maximum value and the minimum value of 3x^4 – 8x^3 + 12x^2 – 48x + 25 on the interval [0, 3].

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answered Jan 23, 2018 by mdsamim (213,225 points)
selected Jan 23, 2018 by sforrest072

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Find both the maximum value and the minimum value of 3x^4 – 8x^3 + 12x^2 – 48x + 25 on the interval [0, 3].

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