Let a piece of length l be cut from the given wire to make a square.
Then, the other piece of wire to be made into a circle is of length (28 − l) m.
Now, side of square = 1/4
Let r be the radius of the circle. Then 
The combined areas of the square and the circle (A) is given by,
By second derivative test, the area (A) is the minimum when 
Hence, the combined area is the minimum when the length of the wire in making the
