The maximum value of [x(x-1)+1]^1/3,0≤ x≤ 1 is

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asked Jan 23, 2018 in Mathematics by sforrest072 (157,439 points) 61 411 949

The maximum value of [x(x-1)+1]1/3,0≤ x≤ 1 is

(A) (1/3)1/3              (B)     1/2

(C)    1                         (D)   0

1 Answer

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answered Jan 23, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 23, 2018 by sforrest072
 
Best answer

Then, we evaluate the value of f at critical point X= 1/2 and at the end points of the interval [0, 1] {i.e., at x = 0 and x = 1}.

Hence, we can conclude that the maximum value of f in the interval [0, 1] is 1.
The correct answer is C.

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