Solution: tan (A + B) = √3
⇒ tan (A + B) = tan 60°
⇒ (A + B) = 60° ... (i)
tan (A – B) = 1/√3
⇒ tan (A - B) = tan 30°
⇒ (A - B) = 30° ... (ii)
Adding (i) and (ii), we get
A + B + A - B = 60° + 30°
2A = 90°
A= 45°
Putting the value of A in equation (i)
45° + B = 60°
⇒ B = 60° - 45°
⇒ B = 15°
Thus, A = 45° and B = 15°