Show that cos 38° cos 52° – sin 38° sin 52° = 0

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asked May 7, 2017 in Mathematics by Rohit Singh (61,782 points) 35 133 357

1 Answer

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answered May 7, 2017 by sforrest072 (157,439 points) 61 410 939
selected May 7, 2017 by Rohit Singh
 
Best answer

Solution:

cos 38° cos 52° - sin 38° sin 52°
= cos (90° - 52°) cos (90°-38°) - sin 38° sin 52°
= sin 52° sin 38° - sin 38° sin 52° = 0

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