Find the intercepts cut off by the plane 2x+y-z=5

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asked Jan 25, 2018 in Mathematics by sforrest072 (157,439 points) 61 411 949
Find the intercepts cut off by the plane 2x+y-z=5

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answered Jan 25, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 25, 2018 by sforrest072
 
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2x+y-z =5                   ....... (1)

Dividing both sides of equation (1) by 5, we obtain

It is known that the equation of a plane in intercept form is   , where a, b, c are the intercepts cut off by the plane at x, y, and z axes respectively. Therefore, for the given equation,

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