Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3, respectively.

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asked Jan 25, 2018 in Mathematics by Annu Priya (18,055 points) 24 45 84

Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3, respectively.

1 Answer

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answered Jan 25, 2018 by Annu Priya (18,055 points) 24 45 84
 
Best answer

The required number when divides 280 and 1245 leaves the remainder 4 and 3, this means
280- 4 = 276 and 1245 – 3 = 1245 – 3 = 1242 are completely divisible by the number
∴ The required number = HCF of 276 and 1242
By applying Euclid’s division lemma
1242 = 276 × 4 + 138
276 = 138 × 2 + 0
∴ HCF = 138
Hence the required numbers is 138

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