Question

Find the equation of the plane passing through the point (−1, 3, 2) and perpendicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + z = 0.

Answer 1

The equation of the plane passing through the point (−1, 3, 2) is a (x + 1) + b (y − 3) + c (z − 2) = 0 … (1) where, a, b, c are the direction ratios of normal to the plane.

Substituting the values of a, b, and c in equation (1), we obtain 

This is the required equation of the plane.