Find the equation of the plane which contains the line of intersection of the planes vector r.(i+2j+3k) -4 =0 vector r.(2i+j-k)+5=0

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asked Jan 25, 2018 in Mathematics by sforrest072 (157,439 points) 63 448 1289
edited Mar 7, 2018 by Vikash Kumar

Find the equation of the plane which contains the line of intersection of the planes

vector r.(i+2j+3k) -4 =0 vector r.(2i+j-k)+5=0

vector r.(5i+3j-6k)+8=0 and which is perpendicular to the plane

1 Answer

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answered Jan 25, 2018 by mdsamim (213,225 points) 5 10 23
selected Jan 25, 2018 by sforrest072
 
Best answer

The equations of the given planes are

The equation of the plane passing through the line intersection of the plane given in equation (1) and equation (2) is

The plane in equation (3) is perpendicular to the plane, 

This is the vector equation of the required plane.
The Cartesian equation of this plane can be obtained by substituting in equation (3).

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