Minimise and Maximise Z = x + 2y subject to x+2y≥100,2x -y≤0,2x+y ≤200;x,y≥0.

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asked Jan 27, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949
edited Mar 6, 2018 by faiz

Minimise and Maximise Z = x + 2y subject to x+2y≥100,2x -y≤0,2x+y ≤200;x,y≥0.

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answered Jan 27, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 27, 2018 by sforrest072
 
Best answer

The feasible region determined by the constraints, x + 2y ≥ 100, 2x − y ≤ 0, 2x + y ≤ 200, x ≥ 0, and y ≥ 0, is as follows.

The corner points of the feasible region are A(0, 50), B(20, 40), C(50, 100), and D(0, 200).
The values of Z at these corner points are as follows.

The maximum value of Z is 400 at (0, 200) and the minimum value of Z is 100 at all the points on the line segment joining the points (0, 50) and (20, 40).

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