It is given that
x = t2 +1 ...(1)
y = 2t + 1 ...(2)
From (1) and (2), we get
(y – 1)2 = 4 (x – 1) ...(3)
Let Y = y – 1 and X = x – 1
Then from equation (3) we have
⇒ Y2 = 4X
Equation of the directrix for parabola Y2 = 4X is:
X = –1
⇒ x – 1 = –1
⇒ x = 0
This is the required equation of directrix.