If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?

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asked Jan 27, 2018 in Mathematics by sforrest072 (157,439 points) 60 409 933
If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?

1 Answer

+1 vote
answered Jan 27, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 7, 2018 by faiz
 
Best answer

In a leap year, there are 366 days i.e., 52 weeks and 2 days.

In 52 weeks, there are 52 Tuesdays. 

Therefore, the probability that the leap year will contain 53 Tuesdays is equal to the probability that the remaining 2 days will be Tuesdays. 

The remaining 2 days can be

 Monday and Tuesday

 Tuesday and Wednesday 

Wednesday and Thursday 

Thursday and Friday 

Friday and Saturday 

Saturday and Sunday 

Sunday and Monday 

Total number of cases = 7 

Favourable cases = 2

Probability that a leap year will have 53 Tuesdays = 2/7

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