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3 = 0, then prove that a =b = c =0.

asked Jan 29, 2018 in Mathematics by sforrest072 (157,439 points)

Let a, b, c, k be rational numbers such that k is not a perfect cube. lf a + bk^1/3 + ck^2/3= 0, then prove that a =b = c =0.

1 Answer

answered Jan 29, 2018 by mdsamim (213,225 points)
selected Jan 29, 2018 by sforrest072

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Let a, b, c, k be rational numbers such that k is not a perfect cube. lf a + bk^1/3 + ck^2/3 = 0, then prove that a =b = c =0.

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