Solve the following systems of equations: 6/(x+y) = 7/(x-y) +3; 1/2(x+y) = 1/a(x-y), where x+y ≠0 and x-y ≠0

+1 vote
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asked Feb 2, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 943

Solve the following systems of equations:

6/(x+y) = 7/(x-y) +3

1/2(x+y) = 1/a(x-y), where x+y ≠0 and x-y ≠0

1 Answer

+1 vote
answered Feb 2, 2018 by mdsamim (213,225 points) 5 10 15
selected Feb 2, 2018 by sforrest072
 
Best answer

Hence, solution of the system of equation is x= -5/4, y = -1/4

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