The perpendicular from A on side BC of a ΔABC intersects BC at D such that DB =3CD (see Fig. 7.43). Prove that? 2AB^2 = 2 AC^2 + BC^2 .

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answered Feb 3, 2018 by Vikash Kumar (144,729 points)

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The perpendicular from A on side BC of a ΔABC intersects BC at D such that DB =3CD (see Fig. 7.43). Prove that? 2AB^2 = 2 AC^2 + BC^2 .

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