Prove that, in a right triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.

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asked Feb 3, 2018 in Mathematics by Kundan kumar (49,132 points) 34 379 1011

Prove that, in a right triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
Using the above, do the following:
Prove that, in a ΔABC, if AD is perpendicular to BC, then AB2+CD2=AC2+BD2

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answered Feb 3, 2018 by Vikash Kumar (144,729 points) 8 11 21
 
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