Let AB be the tree of height h metres standing on the bank of a river.Let C be the position of man standing on the opposite bank of the river such that BC=x m. Let D be the new position of the man. It is given that CD=40m and the angle of elevation of the top of the tree at C and D are 60º and 30º, respectively,i.e,

Hence, the height of the tree is 34.64m and width of the river is 20m.