The slope of the line making an angle 2π/3 with the positive x-axis is m= tan [2π/3]= - √3
Now, the equation of the line passing through point (0, 2) and having a slope -√3 is
The slope of line parallel √3x + y - 2 = 0 is -√3 to line.
It is given that the line parallel to line √3 + y - 2 = 0 crosses the y-axis 2 units below
the origin i.e., it passes through point (0, –2).
Hence, the equation of the line passing through point (0, –2) and having a slope -√3 is
