Let AB be the line segment between the axes such that point R (h, k) divides AB in the ratio 1: 2.
Let the respective coordinates of A and B be (x, 0) and (0, y).
Since point R (h, k) divides AB in the ratio 1: 2, according to the section formula,
Therefore, the respective coordinates of A and B are [ 3h/2,0 ] and (0, 3k).
Now, the equation of line AB passing through points [3h/2,0 ] and (0, 3k) is
Thus, the required equation of the line is 2kx + hy = 3hk