Let A be the event that none of the selected tickets bear number exceeding 25.
Then required probability 
Now, total numbers of ways of drawing three tickets out of 30 is 30C3
∴ Total number of elementary event = 30C3
and three tickets are drawn from tickets bearing number 1 to 25 can be done in 25C3 ways
∴ Favourable number of elementary event = 25C3
