Find equation of the line perpendicular to the line x – 7y + 5 = 0 and having x intercept 3.

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asked Feb 8, 2018 in Mathematics by Rohit Singh (61,782 points) 35 133 357
Find equation of the line perpendicular to the line x – 7y + 5 = 0 and having x intercept 3.

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answered Feb 8, 2018 by sameer (82,980 points) 5 11 37
The given equation of line is x – 7y + 5 = 0. or, y = 1/7 X + 5/7

which is of the form y = mx + c

∴Slope of the given line  = 1/7

The slope of the line perpendicular to the line having a slope of 1/7 is  m = - 1/(1/7) = -7

The equation of the line with slope –7 and x-intercept 3 is given by y = m (x – d)
⇒ y = –7 (x – 3)
⇒ y = –7x + 21
⇒ 7x + y = 21
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