The equation of the given line is x/4 + y/6 =1.
This equation can also be written as 3x + 2y – 12 = 0
y= -3/2x +6,which is of the form y = mx + c
∴ Slope of the = - 3/2 given line
∴ Slope of line perpendicular to the given line = -1/(3-/2) =2/3
Let the given line intersect the y-axis at (0, y).
On substituting x with 0 in the equation of the given line, we obtain y/6 = 1=> y =6
The given line intersects the y-axis at (0, 6).
The equation of the line that has a slope of 2/3 and passes through point (0, 6) is
Thus, the required equation of the line is 2x – 3y + 18 = 0.
