A person standing at the junction (crossing) of two straight paths represented by the equations 2x – 3y + 4 = 0

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asked Feb 9, 2018 in Mathematics by Rohit Singh (61,782 points) 35 133 357

A person standing at the junction (crossing) of two straight paths represented by the equations 2x – 3y + 4 = 0 and 3x + 4y – 5 = 0 wants to reach the path whose equation is 6x – 7y + 8 = 0 in the least time. Find equation of the path that he should follo

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answered Feb 9, 2018 by sameer (82,980 points) 5 11 37

The equations of the given lines are

2x – 3y + 4 = 0 …………………. (1)
3x + 4y – 5 = 0 …………………. (2)
6x – 7y + 8 = 0 ……………….… (3)
The person is standing at the junction of the paths represented by lines (1) and (2).
On solving equations (1) and (2), we obtain .x = -1/17 and y = 22/17.
Thus, the person is standing at point ( - 1/17 , 22/17)
The person can reach path (3) in the least time if he walks along the perpendicular line

to (3) from point ( - 1/17 , 22/17)

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