Answer 10:
Foci (±5, 0), the transverse axis is of length 8.
Here, the foci are on the x-axis.
Therefore, the equation of the hyperbola is of the form X2/a2 - Y2/b2 =1.
Since the foci are (±5, 0), c = 5.
Since the length of the transverse axis is 8, 2a = 8 ⇒ a = 4.
We know that a2 + b2 = c2.
∴42 + b2 = 52
⇒ b2 = 25 – 16 = 9
Thus, the equation of the hyperbola is X2/16 - Y2/9 =1.
