Let AB be the rod making an angle θ with OX and P (x, y) be the point on it such that AP = 3 cm.
Then, PB = AB – AP = (12 – 3) cm = 9 cm [AB = 12 cm]
From P, draw PQ⊥OY and PR ⊥ OX.


Thus, the equation of the locus of point P on the rod is X2/81 + Y2/9 =1.