In a ΔABC, AD is the bisector of ∠A, meeting side BC at D. If AB = 10 cm, AC = 6 cm and BC = 12 cm, find BD and DC.

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asked Feb 10, 2018 in Mathematics by sforrest072 (157,439 points) 60 409 936
In a ΔABC, AD is the bisector of ∠A, meeting side BC at D.

If AB = 10 cm, AC = 6 cm and BC = 12 cm, find BD and DC.

1 Answer

+1 vote
answered Feb 10, 2018 by mdsamim (213,225 points) 5 10 15
selected Feb 10, 2018 by sforrest072
 
Best answer

In ΔABC, AD is the bisector of ∠A.
We know 
that, the internal bisector of an angle of a triangle divides the opposite
side internally in the ratio of the sides containing the angle.

∴ BD = 7.5 cm and DC = 12 – x = 12 – 7.5 = 4.5 cm
Hence, BD = 7.5 cm and DC = 4.5 cm​

In Fig. 4.57, AE is the bisector of the exterior ∠CAD meeting BC produced in E. If AB = 10cm, AC = 6cm and BC = 12 cm, find CE.

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