How many terms of G.P. 3, 3^2, 3^3 … are needed to give the sum 120?

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asked Feb 10, 2018 in Mathematics by Rohit Singh (61,782 points) 35 133 354

How many terms of G.P. 3, 32, 33 … are needed to give the sum 120?

1 Answer

+1 vote
answered Feb 10, 2018 by sameer (82,980 points) 5 11 37
selected Feb 14, 2018 by sanjeev
 
Best answer

The given G.P. is 3, 32, 33 …
Let n terms of this G.P. be required to obtain the sum as 120. =(1−) / 1−

Thus, four terms of the given G.P. are required to obtain the sum as 120.

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