Question

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, PB = 3 cm, AQ = 1.5 cm, QC = 4.5 m, prove that area of ΔAPQ is one-sixteenth of the area of ABC.

Answer 1

We have,
AP = 1 cm, PB = 3 cm, AQ = 1.5 cm and QC = 4.5 m
In ΔAPQ and ΔABC