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If sin θ =12/13 find (sin^2θ-cos^2θ)/2sinθ cosθ x1/ tan^2θ

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asked Feb 15, 2018 in Mathematics by sforrest072 (157,439 points) ● 63 ● 448 ● 1286

If sin θ =12/13 find (sin2θ-cos2θ)/2sinθ cosθ x1/ tan2θ 
 
 If sin theta =12/13 find (sin2theta-cos2theta)/2sin theta cos theta x1/ tan2 theta

 


 

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answered Feb 15, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 23
selected Feb 15, 2018 by sforrest072
 
Best answer

Let x be the adjacent side
By applying Pythagoras

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