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Prove that [1/(sec^2θ-cos^2θ)+1/(cosec^2θ-sin^2θ)]sin^2θcos^2θ=(1-sin^2θcos^2θ)/(2+sin^2θcos^2θ).

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asked Feb 15, 2018 in Mathematics by Kundan kumar (49,132 points) ● 34 ● 382 ● 1020

Prove that [1/(sec2θ-cos2θ)+1/(cosec2θ-sin2θ)]sin2θcos2θ=(1-sin2θcos2θ)/(2+sin2θcos2θ).

Prove that [1/(sec2  theta-cos2  theta)+1/(cosec2  theta-sin2  theta)]sin2  theta cos2  theta=(1-sin2  theta cos2  theta)/(2+sin2  theta cos2  theta).

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answered Feb 15, 2018 by Vikash Kumar (144,729 points) ● 8 ● 11 ● 21
 
Best answer

  Hence proved

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