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(tan^2 60°+4 cos^2 45°+3 sec^2 30°+5 cos^2 90°)/(cosec 30°+sec 60°−cot^2 30°)

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asked Feb 15, 2018 in Mathematics by sforrest072 (157,439 points) ● 61 ● 410 ● 947

(tan2 60°+4 cos2 45°+3 sec2 30°+5 cos2 90°)/(cosec 30°+sec 60°−cot2 30°)

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+1 vote
answered Feb 15, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Feb 15, 2018 by sforrest072
 
Best answer

By trigonometric ratios we have

commented Mar 26, 2018 by kalasheep77 (10 points)
this answer is incorrect. cos45 is 1/root 2 not 1/root 3. check ur substitution again
commented Mar 26, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
It is corrected now, thanks
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