If A, B, C are interior angles of a triangle ABC, prove that (cos 80°)/(sin 10°)+ cos 59° cosec 31° = 2

1 Answer

answered Feb 16, 2018 by mdsamim (213,225 points)
selected Feb 16, 2018 by sforrest072

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If A, B, C are interior angles of a triangle ABC, prove that (cos 80°)/(sin 10°)+ cos 59° cosec 31° = 2

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