For what value of k,(4-k)x^2+(2k+4)x+(8k+1)=0, is a perfect square

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asked Feb 17, 2018 in Mathematics by Kundan kumar (49,132 points) 34 436 1365

For what value of k,(4-k)x2+(2k+4)x+(8k+1)=0, is a perfect square

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answered Feb 17, 2018 by Vikash Kumar (144,729 points) 8 11 26
 
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Therefore The value of k is ' 0 ' or ' 3 ' for the equation to be a perfect square

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