If the roots the equation ax^2+2bx+c=0 and bx^2-2√(cax) +b=0 are simultaneously real,then prove that b^2-ac

0 votes
16 views
asked Feb 17, 2018 in Mathematics by Kundan kumar (49,132 points) 34 381 1016

If the roots the equation ax2+2bx+c=0 and bx2-2√(cax) +b=0 are simultaneously real,then prove that b2-ac

1 Answer

0 votes
answered Feb 17, 2018 by Vikash Kumar (144,729 points) 8 11 21
 
Best answer

=> given that the roots of these two equations are real. Hence D≥0 i.e, (b2-4ac≥0)

Given that the roots of (1) and (2) are simultaneously real hence equation (3) equation (4)​

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...