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The normal at the point (bt1^2,2bt1) on the parabola y^2=4bx meets the parabola again in the point (bt2^2,2bt2)

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+1 vote
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asked Feb 21, 2018 in Mathematics by ankitdixit (1,339 points) ● 12 ● 50
edited Feb 21, 2018 by Annu Priya

The normal at the point (bt12,2bt1) on the parabola y2=4bx meets the parabola again in the point (bt22,2bt2), then

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+1 vote
answered Feb 21, 2018 by Annu Priya (18,055 points) ● 24 ● 45 ● 82
selected Feb 21, 2018 by sarthaks
 
Best answer

Correct answer is option (B)

Explanation:

Equation of the normal to a parabola y2=4bx at point

{bt12,2bt1} is y=-t1x+2bt1+bt13
As given, it also passes through {bt22,2bt2} then

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