A stone of mass m tied to the end of a string revolves in a vertical circle of radius R. The net forces at the lowest

0 votes
16 views
asked Feb 22, 2018 in Physics by paayal (26,720 points) 4 6 11

A stone of mass m tied to the end of a string revolves in a vertical circle of radius R. The net forces at the lowest and highest points of the circle directed vertically downwards are:
[Choose the correct alternative]

T1 and v1 denote the tension and speed at the lowest point. T2 and v2 denote corresponding values at the highest point.

1 Answer

0 votes
answered Feb 22, 2018 by Vikash Kumar (144,729 points) 8 11 21
 
Best answer

The free body diagram of the stone at the lowest point is shown in the following figure.

According to Newton’s second law of motion, the net force acting on the stone at this point is equal to the centripetal force, i.e.,

Where, v1 = Velocity at the lowest point
The free body diagram of the stone at the highest point is shown in the following figure.

Using Newton’s second law of motion, we have:

Where, v2 = Velocity at the highest point
It is clear from equations (i) and (ii) that the net force acting at the lowest and the highest
points are respectively (
T – mg) and (T + mg).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...