Initial speed of the three-wheeler, u = 36 km/h
Final speed of the three-wheeler, v = 10 m/s
Time, t = 4 s
Mass of the three-wheeler, m = 400 kg
Mass of the driver, m' = 65 kg
Total mass of the system, M = 400 + 65 = 465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be
calculated as: v = u + at
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:
F = Ma
= 465 x (–2.5) = –1162.5 N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
