Ask a Question

Two uniform identical rods each of mass M and length l are joined to form a cross

← Prev Question Next Question →
+2 votes
23 views
asked Feb 28, 2018 in JEE by Ghanshyam mishra (385 points) ● 1 ● 15
recategorized Feb 28, 2018 by Annu Priya

Two uniform identical rods each of mass M and length l are joined to form a cross as shown in figure (10-W15). Find the moment of inertia of the cross about a bisector as shown dotted in the figure.

please solve it !

1 Answer

+2 votes
answered Feb 28, 2018 by Annu Priya (18,055 points) ● 24 ● 45 ● 82
selected Feb 28, 2018 by Ghanshyam mishra
 
Best answer

2x1/12 ml2 sin245 = ml2/12

So, moment of inertia of the cross about bisector is I = ml2/12

← Prev Question Next Question →

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...