Speed of the cyclist, v=27 km/h=7.5m/s
Radius of the circular turn, r = 80 m Centripetal acceleration is given as:
The situation is shown in the given figure:
Suppose the cyclist begins cycling from point P and moves toward point Q. At point Q, he applies the breaks and decelerates the speed of the bicycle by 0.5 m/s2.
This acceleration is along the tangent at Q and opposite to the direction of motion of the cyclist.
Since the angle between ac and at is 90°, the resultant acceleration a is given by:
