A satellite orbits the earth at a height of 400 km above the surface.

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asked Mar 7, 2018 in Physics by shabnam praween (19,050 points) 5 6 8

A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg; mass of the earth = 6.0 ×1024 kg; radius of the earth = 6.4 ×106 m; G = 6.67 × 10–11 N m2 kg–2.

1 Answer

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answered Mar 7, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 7, 2018 by shabnam praween
 
Best answer

Mass of the Earth, M = 6.0 × 1024 kg

Mass of the satellite, m = 200 kg

Radius of the Earth, Re = 6.4 × 106 m

Universal gravitational constant, G = 6.67 × 10–11 Nm2kg–2

Height of the satellite, h = 400 km = 4 × 105 m = 0.4 ×106 m

Total energy of the satellite at height h 

The negative sign indicates that the satellite is bound to the Earth. This is called bound energy of the satellite.

Energy required to send the satellite out of its orbit = – (Bound energy)

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