Question

Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongations of the steel and the brass wires.

Answer 1

Elongation of the steel wire = 1.49 × 10^–4 m

Elongation of the brass wire = 1.3 × 10^–4 m
Diameter of the wires, d = 0.25 m
Hence, the radius of the wires, r = d/2= 0.125 cm
Length of the steel wire, L1 = 1.5 m
Length of the brass wire, L₂ = 1.0 m
Total force exerted on the steel wire:
F₁ = (4 + 6) g = 10 × 9.8 = 98 N
Young’s modulus for steel:

Where,

Elongation of the steel wire = 1.49 × 10^–4 m

Elongation of the brass wire = 1.3 × 10^–4 m