Question

A piece of copper having a rectangular cross section of 15.2 mm × 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain?

Answer 1

Length of the piece of copper, l = 19.1 mm = 19.1 × 10^–3 m

Area of the copper piece:

A = l × b = 19.1 × 10^–3 × 15.2 × 10^–3 = 2.9 × 10^–4 m²

Tension force applied on the piece of copper, F = 44500 N

Modulus of elasticity of copper, η = 42 × 10⁹ N/m²