What is the density of water at a depth where pressure is 80.0 atm,What is the density of water at a depth where pressure is 80.0 atm,

Question

What is the density of water at a depth where pressure is 80.0 atm, given that its density at the surface is 1.03 × 10³ kg m^–3?

Answer 1

Let the given depth be h.
Pressure at the given depth, p = 80.0 atm = 80 × 1.01 × 10⁵ Pa
Density of water at the surface, ρ1 = 1.03 × 10³ kg m^–3
Let ρ₂ be the density of water at the depth h.
Let V₁ be the volume of water of mass m at the surface.
Let V₂ be the volume of water of mass m at the depth h.
Let ΔV be the change in volume.

Therefore, the density of water at the given depth (h) is 1.034 × 10³ kg m^–3.